(5x+4)(2x^2-13x-7)=0

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Solution for (5x+4)(2x^2-13x-7)=0 equation: 


Simplifying
(5x + 4)(2x2 + -13x + -7) = 0

Reorder the terms:
(4 + 5x)(2x2 + -13x + -7) = 0

Reorder the terms:
(4 + 5x)(-7 + -13x + 2x2) = 0

Multiply (4 + 5x) * (-7 + -13x + 2x2)
(4(-7 + -13x + 2x2) + 5x * (-7 + -13x + 2x2)) = 0
((-7 * 4 + -13x * 4 + 2x2 * 4) + 5x * (-7 + -13x + 2x2)) = 0
((-28 + -52x + 8x2) + 5x * (-7 + -13x + 2x2)) = 0
(-28 + -52x + 8x2 + (-7 * 5x + -13x * 5x + 2x2 * 5x)) = 0
(-28 + -52x + 8x2 + (-35x + -65x2 + 10x3)) = 0

Reorder the terms:
(-28 + -52x + -35x + 8x2 + -65x2 + 10x3) = 0

Combine like terms: -52x + -35x = -87x
(-28 + -87x + 8x2 + -65x2 + 10x3) = 0

Combine like terms: 8x2 + -65x2 = -57x2
(-28 + -87x + -57x2 + 10x3) = 0

Solving
-28 + -87x + -57x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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